loc(3I)
LOC - Obtains the address of a variable
As shipped in IRIX 6.5.30. Last changed in IRIX 6.5.19.
NAME LOC - Obtains the address of a variable SYNOPSIS LOC ([I=]i) STANDARDS Fortran extension DESCRIPTION LOC returns the address of a variable, constant, or array. It accepts the following arguments: i The variable for which the address is being requested. Specify a variable of any data type. LOC can be used to define a Cray pointer. Just like a variable in common storage, a Cray pointee, Cray pointer, or the argument to LOC is stored in memory before a call to an external procedure and is read out of memory at its next reference. The variable is also stored before a RETURN or END statement of a subprogram. The name of this intrinsic cannot be passed as an argument. WARNINGS LOC is often used to compute the difference of two addresses as an offset. The offset is then used to access one of the arrays by overindexing the other array. RETURN VALUES The hardware architecture determines what is returned; on byte- addressable machines LOC returns a byte address and on word- addressable machines LOC returns a word address. If the -64 compiler option is in effect, the value returned is a KIND=8 value; otherwise, the value returned is a KIND=4 value. EXAMPLES Example 1: Consider the following code: SUBROUTINE SUB(N) COMMON POOL(100000) INTEGER BLK(128), WORD64 REAL A(1000), B(N), C(100000-N-1000) POINTER(PBLK,BLK),(IA,A),(IB,B),(IC,C),(ADDRESS,WORD64) DATA ADDRESS /64/ PBLK = 0 IA = LOC(POOL) IB = IA + 1000 IC = IB + N In effect, WORD64 in this example refers to the contents of absolute address 64; BLK is an array occupying the first 128 words of memory; A is an array of length 1000 located in blank common; B follows A and is of length N; C follows B. A, B, and C are associated with POOL. Similarly, WORD64 is the same as BLK(65), because BLK(1) is at address 0. Example 2: Consider the following code: POINTER (P,B),(P,C) REAL X,B,C P = LOC(X) B = 1.0 C = 2.0 PRINT *,B Because B and C have the same Cray pointer, the assignment of 2.0 to C gives the same value to B; therefore, B prints as 2.0 even though it was assigned 1.0.