integer(3)

NAME
     integer - Perl pragma to compute arithmetic in integer instead of double

SYNOPSIS
         use integer;
         $x = 10/3;
         # $x is now 3, not 3.33333333333333333


DESCRIPTION
     This tells the compiler to use integer operations from here to the end of
     the enclosing BLOCK.  On many machines, this doesn't matter a great deal
     for most computations, but on those without floating point hardware, it
     can make a big difference.

     Note that this affects the operations, not the numbers.  If you run this
     code

         use integer;
         $x = 1.5;
         $y = $x + 1;
         $z = -1.5;

     you'll be left with $x == 1.5, $y == 2 and $z == -1.  The $z case happens
     because unary - counts as an operation.

     See the section on Pragmatic Modules in the perlmod manpage.